"""
Jewels and Stones

You're given strings J representing the types of stones that are jewels, and S representing the stones you have.
Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters.
Letters are case sensitive, so "a" is considered a different type of stone from "A".


Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:

Input: J = "z", S = "ZZ"
Output: 0

Note:

S and J will consist of letters and have length at most 50.
The characters in J are distinct.
"""


class Solution(object):
    def numJewelsInStones(self, J, S):
        """
        :type J: str
        :type S: str
        :rtype: int
        """
        if len(J) == 0 and len(S) == 0 and J == S:
            return 1

        jewels = {}
        for j in J:
            jewels[j] = True

        result = 0
        for s in S:
            if s in jewels:
                result += 1

        return result
